ABCD is a parallelogram such that AB is parallel to DC and DA parallel to CB. The length of side AB is 20cm. E is a point between A and B such that the length of AE is 3cm. F is a point between points D and C. Find the length of DF such that the segment EF divide the parallelogram in two regions with equal areas.
(Geometry)প্রশ্নে বলা হচ্ছে, ABCD একটি সামান্তরিক। AB || DC এবং DA || CB. AB = 20cm. A এবং B এর মধ্যে E এমন একটি বিন্দু যেখানে AE = 3cm. D এবং C এর মধ্যবর্তী বিন্দু F. এখন EF সামান্তরিকটিকে দুইটি অঞ্চলে বিভক্ত কলে DF এর দৈর্ঘ্য বের করুন।
Let, A, be the area of the trapezoid AEFD.
h is the height of the parallelogram.
Now, let A2 be the area of the trapezoid EBCF.
He also have, EB = 20- AE = 17, FC= 20- DF.
We now substitute EB and F in
For EF to divide the parallelogram into two regions of equal area, we need to have area A, and area
[Multiply both sides by 2 and divide by h]